What does int argc, char *argv[] mean?
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by Greg Treleaven
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Published on 2010-06-11T15:45:43Z
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2010/06/11
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In many C++ IDE's and compilers, when it generates the main function for you, it looks like this:
int main(int argc, char *argv[])
When I code C++ without an IDE, just with a command line compiler, I type:
int main()
without any parameters. What does this mean, and is it vital to my program?
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